Answers Binomial Probability Calculator

What is the probability of at least 2 heads in 5 coin flips?

This is a binomial probability question because each coin flip is an independent trial with the same success probability, and the question asks for a success-count range.

Probability result

81.25%

Exact fraction: 13/16

Decimal: 0.8125

The probability of at least 2 successes is 81.25%.

For a fair coin, the chance of heads on each flip is 1/2. At least 2 heads means adding the probabilities for 2, 3, 4, and 5 heads across the 5 flips.

Worked steps

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  1. Inputs: trials = 5, target successes = 2, p = 0.5, event = at least.
  2. Formula: P(X in range) = sum of C(n, k)p^k(1-p)^(n-k) terms.
  3. Substitute: use C(5, k) with p = 1/2 and 1-p = 1/2.
  4. Steps: evaluate the binomial terms for X >= 2 and combine them.
  5. Result: The probability of at least 2 successes is 81.25%.

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For a fair coin, the chance of heads on each flip is 1/2. At least 2 heads means adding the probabilities for 2, 3, 4, and 5 heads across the 5 flips.

Formula

Probability model

P(E) = favorable outcomes / total outcomes

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Calculation work