Model guide
Why this probability model fits
This is a basic probability problem because you can count the favourable outcomes directly and divide by the full number of equally likely single-card outcomes.
Setup: A single-card draw has 52 equally likely outcomes, and 4 of them are aces.
Replacement: Replacement is not part of the setup because only one card is drawn.
Independence: Independence is not needed here because this is a one-draw event.
Worked solution
7.6923%
Exact fraction: 1/13
Decimal: 0.076923
The probability is 1/13, which is 7.6923%.
- Count the favorable outcomes: 4.
- Count the total equally likely outcomes: 52.
- Use P(E) = favorable outcomes / total outcomes.
- Reduce 4/52 to 1/13.
- State the result as 0.076923 or 7.6923%.
Interactive tool
Run the same scenario in the calculator
This is a basic probability problem because you can count the favourable outcomes directly and divide by the full number of equally likely single-card outcomes.
Formula
Probability model
P(E) = favorable outcomes / total outcomes
Use the model that matches the setup wording.
Probability
0%
Enter values to calculate.
What your result means
The explanation updates with the current inputs.
Calculation work