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What is the probability of not drawing an ace from a standard deck?

This is a basic probability question because you can count favourable outcomes directly and divide by the total equally likely single-card outcomes.

Probability result

92.3077%

Exact fraction: 12/13

Decimal: 0.923077

The probability is 12/13, which is 0.923077 or 92.3077%.

A standard deck has 48 non-aces out of 52 cards. That makes the probability 48 out of 52, which reduces to 12 out of 13 or about 92.31%.

Worked steps

Show your work

  1. Inputs: favorable outcomes = 48, total outcomes = 52.
  2. Formula: P(E) = favorable outcomes / total outcomes.
  3. Substitute: P(E) = 48/52.
  4. Reduce: 48/52 = 12/13.
  5. Result: The probability is 12/13, which is 0.923077 or 92.3077%.

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A standard deck has 48 non-aces out of 52 cards. That makes the probability 48 out of 52, which reduces to 12 out of 13 or about 92.31%.

Formula

Probability model

P(E) = favorable outcomes / total outcomes

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Calculation work