Answers Multiset Permutation Calculator

How many distinct arrangements of the letters in MISSISSIPPI are there?

This is a multiset permutation because all 11 letters are arranged, order matters, and repeated letters must not create duplicate counts. Start by placing the letter into groups.

Exact result

34,650

For item-group counts 4, 4, 2, 1, the number of distinct arrangements is 34,650.

MISSISSIPPI has counts 4,4,2,1 because I and S each appear 4 times, P appears 2 times, and M appears once. Dividing out the repeated-letter swaps leaves only the unique visible arrangements.

Worked steps

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  1. Inputs: item-group counts = 4, 4, 2, 1
  2. Formula: T! / (n1! n2! n3! ...)
  3. Substitute: 11! / (4! 4! 2! 1!)
  4. Steps: start with 39,916,800 and divide by 4! = 24, 4! = 24, 2! = 2, 1! = 1
  5. Result: For item-group counts 4, 4, 2, 1, the number of distinct arrangements is 34,650.

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MISSISSIPPI has counts 4,4,2,1 because I and S each appear 4 times, P appears 2 times, and M appears once. Dividing out the repeated-letter swaps leaves only the unique visible arrangements.

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